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Subject: Re: question # 17


Author:
Flavia Banu
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Date Posted: 19:14:39 01/27/11 Thu
In reply to: Aaron 's message, "Re: question # 17" on 23:32:11 01/26/11 Wed

Hmmm, I'm not sure what your book says for choices C and D, mine says: (C) rad2 (D)2rad2 (this is actually the answer I got). I sort of cheated - I found d = sqrt((16/x^2+x^2)), entered it in y1, found the min value of y1 which was 2.8... which is 2rad2. Hope this helps!

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Replies:
Subject Author Date
Re: question # 17Rachel (I SEE THE LIGHT)19:35:32 01/27/11 Thu


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