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Subject: Re: Finding equation of a parabola with vertex at Oy and passing thru (2,2) Author: QUITTNER [ Next Thread | Previous Thread | Next Message | Previous Message ] Date Posted: 11:19:31 11/11/03 Tue In reply to: lanie 's message, "Finding equation of a parabola with vertex at Oy and passing thru (2,2)" on 18:00:29 11/06/03 Thu You wrote: "Finding equation of a parabola with vertex at Oy and passing thru (2,2)" ..... I suppose this means that the vertex is at the ORIGIN (0,0), and that one point is at (2,2) ..... We have the general equation y-k=a(x-h)^2 where, in our case k and h are both zero. Therefore y=a*x^2 and in our case 2=a*2^2=4a. Therefore a=1/2 and y=(1/2)*x^2 ..... Check it out: if x=2 then y=1/2 of 4, y=2 OK [ Next Thread | Previous Thread | Next Message | Previous Message ]