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Subject: Re: Finding the Equation of a Parabola using the vertex and 1 point Author: Kristen [ Next Thread | Previous Thread | Next Message | Previous Message ] Date Posted: 09:33:14 10/18/04 Mon In reply to: QUITTNER 's message, "Re: Finding the Equation of a Parabola using the vertex and 1 point" on 09:11:49 11/10/03 Mon y=a(h-h)* +k (*=^2) fill in your points 15=a(7-5)*+12 15-12=a(2)* 3=4a a=3/4 Standard, fill in a and vertex a(x-h)*+k 3/4(x-5)*+12 thus that is your equation in standard form [ Next Thread | Previous Thread | Next Message | Previous Message ]

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[> [> [> Subject: Re: Finding the Equation of a Parabola using the vertex and 1 point Author: Kristen [ Edit | View ] Date Posted: 09:34:19 10/18/04 Mon >y=a(h-h)* +k (*=^2) >fill in your points >15=a(7-5)*+12 >15-12=a(2)* >3=4a >a=3/4 > >Standard, fill in a and vertex >a(x-h)*+k >3/4(x-5)*+12 > >thus that is your equation in standard form [ Post a Reply to This Message ]

[> [> [> Subject: Re: Finding the Equation of a Parabola using the vertex and 1 point Author: QUITTNER [ Edit | View ] Date Posted: 07:49:56 10/19/04 Tue Given that the vertex has coordinates (a,b), and the one give point has coordinats (x1,y1) Starting with the equation of a parabola: (y-a)^2 = k * (x-b) We know a and b (the vertex), and we can then use (y1-a)^2 = k * (x1-b) to find k [ Post a Reply to This Message ]

[> [> [> [> Subject: Re: Finding the Equation of a Parabola using the vertex and 1 point Author: QUITTNER [ Edit | View ] Date Posted: 08:05:59 10/19/04 Tue CORRECTION: (Reversing a and b in my previous post): Given that the vertex has coordinates (a,b), and the one given point has coordinates (x1,y1) Starting with the equation of a parabola: (y-b)^2 = k * (x-a) We know a and b (the vertex), and we can then use (y1-b)^2 = k * (x1-a) to find k [ Post a Reply to This Message ]