Re: coordinate geometry: linear equations in two variables -- Mathematics Help

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Subject: Re: coordinate geometry: linear equations in two variables

Author:
NICK (http://calculator.tutorvista.com)

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Date Posted: 00:22:07 11/03/11 Thu
In reply to: Misty Bowman 's message, "coordinate geometry: linear equations in two variables" on 18:06:25 06/18/05 Sat

Steps for Calculating Compound Interest
Step 1 :

Formula for calculating the total amount,

Total amount = P(1+(R/100))n.

Compound interest = Total amount - principal.

Step 2 :

When the Time is given in months then:

1 month= 0.08, 2 months = 0.17, 3 months= 0.25, 4 months= 0.33, 5 months= 0.42, 6 months= 0.50, 7 months= 0.58, 8 months= 0.67, 9 months= 0.75, 10 months= 0.83 and 11 months= 0.92.

http://calculator.tutorvista.com/math/33/compound-interest-calculator.html

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[> Subject: Re: coordinate geometry: linear equations in two variables

Author:
Engr. Lawrence peter
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Date Posted: 09:38:03 09/08/12 Sat

>what is the equation of the line that contains the
>points with (x,y)coordinates(-3,7) and (5,-1)? I need
>to know how to do this problem step by step.
solution
lets assume that (-3,7) is coordinate 1 i.e x1 is -3 y1 is 7 and (5,-1) is coordinate 2 i.e x2 is 5 and y2 is -1
using d formula
y-y1/x-x1=y2-y1/x2-x1
by putting in the values of the coordinate u get
y-7/x-(-3)= -1-7/5-(-3)
y-7/x+3 =-8/5+3
y-7/x+3= -8/8
y-7/x+3=-1/1
by cross multiplying you get
1(y-7)=-1(x+3)
open the brackets you get
y-7=-x-3
collect like terms you get
y+x=7-3
y+x=4
this is your required equatn thank you hope I helped

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[> [> Subject: Re: coordinate geometry: linear equations in two variables

Author:
MK (Thankful)
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Date Posted: 13:49:40 08/19/15 Wed

>>what is the equation of the line that contains the
>>points with (x,y)coordinates(-3,7) and (5,-1)? I need
>>to know how to do this problem step by step.
> solution
>lets assume that (-3,7) is coordinate 1 i.e x1 is -3
>y1 is 7 and (5,-1) is coordinate 2 i.e x2 is 5 and y2
>is -1
>using d formula
> y-y1/x-x1=y2-y1/x2-x1
>by putting in the values of the coordinate u get
>y-7/x-(-3)= -1-7/5-(-3)
>y-7/x+3 =-8/5+3
>y-7/x+3= -8/8
>y-7/x+3=-1/1
>by cross multiplying you get
>1(y-7)=-1(x+3)
>open the brackets you get
>y-7=-x-3
>collect like terms you get
>y+x=7-3
>y+x=4
>this is your required equatn thank you hope I helped

It definitely helped, sir. THANKS ALOT!

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