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Subject: #49!!!! Author: merian [ Next Thread | Previous Thread | Next Message | Previous Message ] Date Posted: 11:36:18 08/25/03 Mon can u explain 2.1 #49??? [ Next Thread | Previous Thread | Next Message | Previous Message ]

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[> Subject: Re: #49!!!! Author: Benny [ Edit | View ] Date Posted: 13:15:45 08/25/03 Mon >can u explain 2.1 #49??? for: (a) you just graph it, so....from -2Pi to 0, you would have the sin x graph, and from 0 to 2Pi you would have the cos x graph. (b) it's basically asking you at what points in the graph you just produce will the limit exist (both left and right). In this case, you take away the endpoints, because only a one-sided limit exist for endpoints. And you can take away c=0 because the left limit does not equal the right limit. So you should have the interval (-2Pi,0)U(0,2Pi) as your answer because any points in that interval will have a limit. (c) this part is asking you, which point on your graph only has a left handed limit (which means coming from the left and goes to the right). In this case, only c=2Pi. (d) this part is the opposite of part (c), which point will only have a right handed limit (coming from the right and goes to the left). In this case only c=-2Pi If it's not clear, ask me again in class, I can explain it better on the chalk board. [ Post a Reply to This Message ]