Re: Linked list - remove item -- SkilaboÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ°askjÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ³ÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ°a TÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ¶lvunarfrÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ¦ÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂÃÂ°i 2

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Date Posted: 15:07:09 03/05/02 Tue
Author: Hj�lmt�r
Subject: Re: Linked list - remove item
In reply to: 's message, "Linked list - remove item" on 08:32:06 03/05/02 Tue

>Afhverju getur �etta fall ekki fjarl�gt seinasta
>staki� �r listanum. �a� er eins og a� �a� se ekki til!
>
>hva� er vitlaust � �essu:
>
>
>int remove(node *x, node *target)
>{
>while(x->next != NULL) {
> if(x->next == target) {x->next= x->next->next; delete
>target; return 0; }
>
> x = x->next;
> }
>
> return -1;
>}

�egar �� segir "seinasta staki�", �� ttu vi� �egar a�eins er einn hn�tur eftir, er �a� ekki? �g s� ekki anna� en
a� �etta virki til a� fjarl�gja AFTASTA staki� �r listanum.

�essi k�di virkar bara til a� taka �t hn�t �r lista sem hefur haushn�t (�.e. dummy hn�t fremst). Annars getur�u
ekki teki� �t fremsta hn�tinn, �v� a� ef x bendir beint � hann �� ver�ur skilyr�i� " x->next == target " aldrei
satt. �v� �� er " x == target ". �a� ver�ur �v� a� nota haushn�t til a� x geti alltaf bent � hn�tinn FYRIR FRAMAN
hn�tinn sem target bendir �.

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