Re: Finding the Equation of a Parabola -- Mathematics Help

[ Show ]

Support VoyForums

[ Shrink ]

VoyForums Announcement: Programming and providing support for this service has been a labor of love since 1997. We are one of the few services online who values our users' privacy, and have never sold your information. We have even fought hard to defend your privacy in legal cases; however, we've done it with almost no financial support -- paying out of pocket to continue providing the service. Due to the issues imposed on us by advertisers, we also stopped hosting most ads on the forums many years ago. We hope you appreciate our efforts.

Show your support by donating any amount. (Note: We are still technically a for-profit company, so your contribution is not tax-deductible.) PayPal Acct: Feedback:

Donate to VoyForums (PayPal):

[ Login ] [ Contact Forum Admin ] [ Main index ] [ Post a new message ] [ Search | Check update time | Archives: 1 ]

Subject: Re: Finding the Equation of a Parabola

Author:
QUITTNER

[ Next Thread | Previous Thread | Next Message | Previous Message ]

Date Posted: 10:00:46 02/22/05 Tue
In reply to: Justin 's message, "Re: Finding the Equation of a Parabola" on 15:55:44 02/21/05 Mon

>>> if the problem says express each equation in the form y=a(x-h)�+k or x=a(y-k)�+h, then how do you do y=2x�-12x+6?
..... First you selcet the proper equation. Here the left side is y, therefore use y=a(x-h)^2+k. Expand this to get
y=a*(x^2-2hx+h^2) + k or
y=a(x^2) - 2ahx +a(h^2) + k (1) We also know
y=2x^2) - 12x + 6 (2)
Compare the coeficients of equation (1) with those of (2):
a=2 4h=12, h=3 18+k=6, k=-12

Always check your answers:
y=2*(x-3)^2 - 12 = 2*(x^2-6x+9) - 12 =
y=2*(x^2)-12x+18-12 OK

[ Next Thread | Previous Thread | Next Message | Previous Message ]