Re: Finding the Equation of a Parabola using the vertex and 1 point -- Mathematics Help

[ Show ]

Support VoyForums

[ Shrink ]

VoyForums Announcement: Programming and providing support for this service has been a labor of love since 1997. We are one of the few services online who values our users' privacy, and have never sold your information. We have even fought hard to defend your privacy in legal cases; however, we've done it with almost no financial support -- paying out of pocket to continue providing the service. Due to the issues imposed on us by advertisers, we also stopped hosting most ads on the forums many years ago. We hope you appreciate our efforts.

Show your support by donating any amount. (Note: We are still technically a for-profit company, so your contribution is not tax-deductible.) PayPal Acct: Feedback:

Donate to VoyForums (PayPal):

[ Login ] [ Contact Forum Admin ] [ Main index ] [ Post a new message ] [ Search | Check update time | Archives: 1 ]

Subject: Re: Finding the Equation of a Parabola using the vertex and 1 point

Author:
leslie ann peji

[ Next Thread | Previous Thread | Next Message | Previous Message ]

Date Posted: 03:48:04 08/16/10 Mon
In reply to: QUITTNER 's message, "Re: Finding the Equation of a Parabola using the vertex and 1 point" on 09:11:49 11/10/03 Mon

the x and y coordinates of the vertex gives the values of h and k respectively
hence, h=5 and k=12

the equation can be written as y=a(x-5)^2+12 "a" can be found using the fact that the point (7, 15)is on the graph of the line. 15= a(7-5)^2+12
15=4a+12
4a=15-12
a=-3/4
therefore, y=a(x-h)^2+12

[ Next Thread | Previous Thread | Next Message | Previous Message ]

Replies:

[> [> [> Subject: Re: Finding the Equation of a Parabola using the vertex and 1 point

Author:
leslie ann peji
[ Edit | View ]

Date Posted: 03:54:36 08/16/10 Mon

>the x and y coordinates of the vertex gives the values
>of h and k respectively
> hence, h=5 and k=12
>
>the equation can be written as y=a(x-5)^2+12 "a" can
>be found using the fact that the point (7, 15)is on
>the graph of the line. 15= a(7-5)^2+12
> 15=4a+12
> 4a=15-12
> a=-3/4
> therefore, y=a(x-h)^2+12 answer: y=-3/4(x-5)^2+12

[ Post a Reply to This Message ]

[> [> [> Subject: Re: Finding the Equation of a Parabola using the vertex and 1 point
Author: simon (sad) [ Edit \| View ]	Date Posted: 05:56:35 03/23/13 Sat I am finding it hard to find the equation of the parabola given the vertex(7,-2) and a x-intercept(4,0). How will i get or find the equation of the parabola. [ Post a Reply to This Message ]