Re: Finding the Equation of a Parabola using the vertex and 1 point -- Mathematics Help

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Subject: Re: Finding the Equation of a Parabola using the vertex and 1 point

Author:
leslie ann peji

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Date Posted: 03:54:36 08/16/10 Mon
In reply to: leslie ann peji 's message, "Re: Finding the Equation of a Parabola using the vertex and 1 point" on 03:48:04 08/16/10 Mon

>the x and y coordinates of the vertex gives the values
>of h and k respectively
> hence, h=5 and k=12
>
>the equation can be written as y=a(x-5)^2+12 "a" can
>be found using the fact that the point (7, 15)is on
>the graph of the line. 15= a(7-5)^2+12
> 15=4a+12
> 4a=15-12
> a=-3/4
> therefore, y=a(x-h)^2+12 answer: y=-3/4(x-5)^2+12

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[> [> [> Subject: Re: Finding the Equation of a Parabola using the vertex and 1 point
Author: simon (sad) [ Edit \| View ]	Date Posted: 05:56:35 03/23/13 Sat I am finding it hard to find the equation of the parabola given the vertex(7,-2) and a x-intercept(4,0). How will i get or find the equation of the parabola. [ Post a Reply to This Message ]